Calculus Find dy/dx x^2xyy^2=1 x2 − xy y2 = 1 x 2 x y y 2 = 1 Differentiate both sides of the equation d dx (x2 −xy y2) = d dx (1) d d x ( x 2 x y y 2) = d d x ( 1) Differentiate the left side of the equation Tap for more steps −xy' 2yy' 2x−y x y ′ 2 y y ′ 2 x y Since 1 1 is constant with respect to xAnswer (1 of 10) Using the identity x^2 y^2 2xy = (xy)^2 x^2 y^2 2xy 1 = (xy)^2 1 = (xy1)*(xy1) We therefore have 2 factors (xy1) and (xy1)Answer to (x^2 1) y'
The Solution Of 1 X 2 Dy Dx 2xy Xsqrt 1 X 2 0 Is A Y 1 X 2 1 Sqrt 1 X 2 C B Y 1 X 2 Sqrt 1 X 2 C C Y 1 X 2 3 2 Sqrt 1 X 2 C D None Of These
